Base | Representation |
---|---|
bin | 110111111000101101… |
… | …0001110111110011011 |
3 | 102110210000002021201001 |
4 | 1233301122032332123 |
5 | 3431242130200011 |
6 | 131044523005431 |
7 | 11446031513332 |
oct | 1576132167633 |
9 | 373700067631 |
10 | 120014303131 |
11 | 46996a44298 |
12 | 1b314669877 |
13 | b418154768 |
14 | 5b471cad19 |
15 | 31c637d7c1 |
hex | 1bf168ef9b |
120014303131 has 2 divisors, whose sum is σ = 120014303132. Its totient is φ = 120014303130.
The previous prime is 120014303053. The next prime is 120014303153. The reversal of 120014303131 is 131303410021.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-120014303131 is a prime.
It is a super-2 number, since 2×1200143031312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 120014303099 and 120014303108.
It is not a weakly prime, because it can be changed into another prime (120014303161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60007151565 + 60007151566.
It is an arithmetic number, because the mean of its divisors is an integer number (60007151566).
Almost surely, 2120014303131 is an apocalyptic number.
120014303131 is a deficient number, since it is larger than the sum of its proper divisors (1).
120014303131 is an equidigital number, since it uses as much as digits as its factorization.
120014303131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 120014303131 its reverse (131303410021), we get a palindrome (251317713152).
The spelling of 120014303131 in words is "one hundred twenty billion, fourteen million, three hundred three thousand, one hundred thirty-one".
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