Base | Representation |
---|---|
bin | 110111111000110111… |
… | …1010110010000010001 |
3 | 102110210101111111002001 |
4 | 1233301233112100101 |
5 | 3431300034303334 |
6 | 131045241354001 |
7 | 11446126535023 |
oct | 1576157262021 |
9 | 373711444061 |
10 | 120019837969 |
11 | 4699a084739 |
12 | 1b316498901 |
13 | b419341b05 |
14 | 5b47c2c013 |
15 | 31c6ac3714 |
hex | 1bf1bd6411 |
120019837969 has 2 divisors, whose sum is σ = 120019837970. Its totient is φ = 120019837968.
The previous prime is 120019837933. The next prime is 120019837981. The reversal of 120019837969 is 969738910021.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 96584208400 + 23435629569 = 310780^2 + 153087^2 .
It is a cyclic number.
It is not a de Polignac number, because 120019837969 - 27 = 120019837841 is a prime.
It is a super-2 number, since 2×1200198379692 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (120019837669) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60009918984 + 60009918985.
It is an arithmetic number, because the mean of its divisors is an integer number (60009918985).
Almost surely, 2120019837969 is an apocalyptic number.
It is an amenable number.
120019837969 is a deficient number, since it is larger than the sum of its proper divisors (1).
120019837969 is an equidigital number, since it uses as much as digits as its factorization.
120019837969 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1469664, while the sum is 55.
The spelling of 120019837969 in words is "one hundred twenty billion, nineteen million, eight hundred thirty-seven thousand, nine hundred sixty-nine".
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