Base | Representation |
---|---|
bin | 11011010010100001010010… |
… | …010001100111011110111011 |
3 | 120201221210110102120122212221 |
4 | 123102201102101213132323 |
5 | 111212401322244004212 |
6 | 1103132222514544511 |
7 | 34165104105316663 |
oct | 3322412221473673 |
9 | 521853412518787 |
10 | 120019946469307 |
11 | 3527319a960895 |
12 | 11564805298137 |
13 | 51c7aa89b1131 |
14 | 218cdd41bd1a3 |
15 | dd1eda84a807 |
hex | 6d28524677bb |
120019946469307 has 2 divisors, whose sum is σ = 120019946469308. Its totient is φ = 120019946469306.
The previous prime is 120019946469277. The next prime is 120019946469413. The reversal of 120019946469307 is 703964649910021.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 120019946469307 - 219 = 120019945945019 is a prime.
It is a super-5 number, since 5×1200199464693075 (a number of 72 digits) contains 55555 as substring.
It is not a weakly prime, because it can be changed into another prime (120019946461307) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60009973234653 + 60009973234654.
It is an arithmetic number, because the mean of its divisors is an integer number (60009973234654).
Almost surely, 2120019946469307 is an apocalyptic number.
120019946469307 is a deficient number, since it is larger than the sum of its proper divisors (1).
120019946469307 is an equidigital number, since it uses as much as digits as its factorization.
120019946469307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 17635968, while the sum is 61.
The spelling of 120019946469307 in words is "one hundred twenty trillion, nineteen billion, nine hundred forty-six million, four hundred sixty-nine thousand, three hundred seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.076 sec. • engine limits •