Base | Representation |
---|---|
bin | 110111111000111010… |
… | …0100101100010110001 |
3 | 102110210111002020221122 |
4 | 1233301310211202301 |
5 | 3431300412230223 |
6 | 131045331032025 |
7 | 11446144314653 |
oct | 1576164454261 |
9 | 373714066848 |
10 | 120021211313 |
11 | 4699a932533 |
12 | 1b316a3b615 |
13 | b419702c43 |
14 | 5b480a86d3 |
15 | 31c6c955c8 |
hex | 1bf1d258b1 |
120021211313 has 2 divisors, whose sum is σ = 120021211314. Its totient is φ = 120021211312.
The previous prime is 120021211291. The next prime is 120021211327. The reversal of 120021211313 is 313112120021.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 78768351649 + 41252859664 = 280657^2 + 203108^2 .
It is a cyclic number.
It is not a de Polignac number, because 120021211313 - 220 = 120020162737 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 120021211291 and 120021211300.
It is not a weakly prime, because it can be changed into another prime (120021211363) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60010605656 + 60010605657.
It is an arithmetic number, because the mean of its divisors is an integer number (60010605657).
Almost surely, 2120021211313 is an apocalyptic number.
It is an amenable number.
120021211313 is a deficient number, since it is larger than the sum of its proper divisors (1).
120021211313 is an equidigital number, since it uses as much as digits as its factorization.
120021211313 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 120021211313 its reverse (313112120021), we get a palindrome (433133331334).
The spelling of 120021211313 in words is "one hundred twenty billion, twenty-one million, two hundred eleven thousand, three hundred thirteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.097 sec. • engine limits •