Base | Representation |
---|---|
bin | 10110010110110001… |
… | …00000100001100010 |
3 | 1010222110010120210201 |
4 | 23023120200201202 |
5 | 144040021242424 |
6 | 5302543215414 |
7 | 603265312435 |
oct | 131330404142 |
9 | 33873116721 |
10 | 12002134114 |
11 | 50a998a003 |
12 | 23ab5a756a |
13 | 1193731009 |
14 | 81c01581c |
15 | 4a3a42d44 |
hex | 2cb620862 |
12002134114 has 32 divisors (see below), whose sum is σ = 19307502720. Its totient is φ = 5581965312.
The previous prime is 12002134103. The next prime is 12002134121. The reversal of 12002134114 is 41143120021.
It is a junction number, because it is equal to n+sod(n) for n = 12002134091 and 12002134100.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 439714 + ... + 466210.
It is an arithmetic number, because the mean of its divisors is an integer number (603359460).
Almost surely, 212002134114 is an apocalyptic number.
12002134114 is a deficient number, since it is larger than the sum of its proper divisors (7305368606).
12002134114 is a wasteful number, since it uses less digits than its factorization.
12002134114 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 26794.
The product of its (nonzero) digits is 192, while the sum is 19.
Adding to 12002134114 its reverse (41143120021), we get a palindrome (53145254135).
The spelling of 12002134114 in words is "twelve billion, two million, one hundred thirty-four thousand, one hundred fourteen".
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