Base | Representation |
---|---|
bin | 11011010010100011001101… |
… | …011100110100010101011100 |
3 | 120201221222210110010110022120 |
4 | 123102203031130310111130 |
5 | 111212420040312044400 |
6 | 1103133203535542540 |
7 | 34165206240500565 |
oct | 3322431534642534 |
9 | 521858713113276 |
10 | 120022013003100 |
11 | 3527406041125a |
12 | 115650a138aa50 |
13 | 51c8047b823b0 |
14 | 218d14c83716c |
15 | dd20abea1ca0 |
hex | 6d28cd73455c |
120022013003100 has 288 divisors, whose sum is σ = 375690115960320. Its totient is φ = 29408544322560.
The previous prime is 120022013003093. The next prime is 120022013003173. The reversal of 120022013003100 is 1300310220021.
It is a super-2 number, since 2×1200220130031002 (a number of 29 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a self number, because there is not a number n which added to its sum of digits gives 120022013003100.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 5204082169 + ... + 5204105231.
Almost surely, 2120022013003100 is an apocalyptic number.
120022013003100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 120022013003100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (187845057980160).
120022013003100 is an abundant number, since it is smaller than the sum of its proper divisors (255668102957220).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
120022013003100 is a wasteful number, since it uses less digits than its factorization.
120022013003100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 29149 (or 29142 counting only the distinct ones).
The product of its (nonzero) digits is 72, while the sum is 15.
Adding to 120022013003100 its reverse (1300310220021), we get a palindrome (121322323223121).
The spelling of 120022013003100 in words is "one hundred twenty trillion, twenty-two billion, thirteen million, three thousand, one hundred".
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