Base | Representation |
---|---|
bin | 11011010010100011001101… |
… | …011101100100011011100011 |
3 | 120201221222210110111110112211 |
4 | 123102203031131210123203 |
5 | 111212420040334400344 |
6 | 1103133203544102551 |
7 | 34165206242251123 |
oct | 3322431535443343 |
9 | 521858713443484 |
10 | 120022013200099 |
11 | 3527406053626a |
12 | 115650a1464a57 |
13 | 51c8047c20c6a |
14 | 218d14c888c83 |
15 | dd20abee0334 |
hex | 6d28cd7646e3 |
120022013200099 has 2 divisors, whose sum is σ = 120022013200100. Its totient is φ = 120022013200098.
The previous prime is 120022013200091. The next prime is 120022013200109. The reversal of 120022013200099 is 990002310220021.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 120022013200099 - 23 = 120022013200091 is a prime.
It is a super-2 number, since 2×1200220132000992 (a number of 29 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 120022013200099.
It is not a weakly prime, because it can be changed into another prime (120022013200091) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60011006600049 + 60011006600050.
It is an arithmetic number, because the mean of its divisors is an integer number (60011006600050).
Almost surely, 2120022013200099 is an apocalyptic number.
120022013200099 is a deficient number, since it is larger than the sum of its proper divisors (1).
120022013200099 is an equidigital number, since it uses as much as digits as its factorization.
120022013200099 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3888, while the sum is 31.
The spelling of 120022013200099 in words is "one hundred twenty trillion, twenty-two billion, thirteen million, two hundred thousand, ninety-nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •