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120022013200099 is a prime number
BaseRepresentation
bin11011010010100011001101…
…011101100100011011100011
3120201221222210110111110112211
4123102203031131210123203
5111212420040334400344
61103133203544102551
734165206242251123
oct3322431535443343
9521858713443484
10120022013200099
113527406053626a
12115650a1464a57
1351c8047c20c6a
14218d14c888c83
15dd20abee0334
hex6d28cd7646e3

120022013200099 has 2 divisors, whose sum is σ = 120022013200100. Its totient is φ = 120022013200098.

The previous prime is 120022013200091. The next prime is 120022013200109. The reversal of 120022013200099 is 990002310220021.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 120022013200099 - 23 = 120022013200091 is a prime.

It is a super-2 number, since 2×1200220132000992 (a number of 29 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 120022013200099.

It is not a weakly prime, because it can be changed into another prime (120022013200091) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60011006600049 + 60011006600050.

It is an arithmetic number, because the mean of its divisors is an integer number (60011006600050).

Almost surely, 2120022013200099 is an apocalyptic number.

120022013200099 is a deficient number, since it is larger than the sum of its proper divisors (1).

120022013200099 is an equidigital number, since it uses as much as digits as its factorization.

120022013200099 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3888, while the sum is 31.

The spelling of 120022013200099 in words is "one hundred twenty trillion, twenty-two billion, thirteen million, two hundred thousand, ninety-nine".