Base | Representation |
---|---|
bin | 110111111001001011… |
… | …0100010011001001011 |
3 | 102110211002211102110001 |
4 | 1233302112202121023 |
5 | 3431310202030212 |
6 | 131050245503431 |
7 | 11446313053321 |
oct | 1576226423113 |
9 | 373732742401 |
10 | 120030111307 |
11 | 469a49611a7 |
12 | 1b319a11b77 |
13 | b41b4cac02 |
14 | 5b49343d11 |
15 | 31c7952657 |
hex | 1bf25a264b |
120030111307 has 2 divisors, whose sum is σ = 120030111308. Its totient is φ = 120030111306.
The previous prime is 120030111283. The next prime is 120030111329. The reversal of 120030111307 is 703111030021.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 120030111307 - 223 = 120021722699 is a prime.
It is not a weakly prime, because it can be changed into another prime (120030111337) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60015055653 + 60015055654.
It is an arithmetic number, because the mean of its divisors is an integer number (60015055654).
Almost surely, 2120030111307 is an apocalyptic number.
120030111307 is a deficient number, since it is larger than the sum of its proper divisors (1).
120030111307 is an equidigital number, since it uses as much as digits as its factorization.
120030111307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 126, while the sum is 19.
Adding to 120030111307 its reverse (703111030021), we get a palindrome (823141141328).
The spelling of 120030111307 in words is "one hundred twenty billion, thirty million, one hundred eleven thousand, three hundred seven".
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