12003100020221 has 4 divisors (see below), whose sum is σ = 12003181794912. Its totient is φ = 12003018245532.

The previous prime is 12003100020209. The next prime is 12003100020283. The reversal of 12003100020221 is 12202000130021.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12003100020221 - 2⁴² = 7605053509117 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 12003100020196 and 12003100020205.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12003100020521) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 40666775 + ... + 40960868.

It is an arithmetic number, because the mean of its divisors is an integer number (3000795448728).

Almost surely, 2^{12003100020221} is an apocalyptic number.

It is an amenable number.

12003100020221 is a deficient number, since it is larger than the sum of its proper divisors (81774691).

12003100020221 is an equidigital number, since it uses as much as digits as its factorization.

12003100020221 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 81774690.

The product of its (nonzero) digits is 48, while the sum is 14.

Adding to 12003100020221 its reverse (12202000130021), we get a palindrome (24205100150242).

The spelling of 12003100020221 in words is "twelve trillion, three billion, one hundred million, twenty thousand, two hundred twenty-one".