Base | Representation |
---|---|
bin | 1010111010101011000010… |
… | …0101010101001110101011 |
3 | 1120111111002202112110020201 |
4 | 2232222300211111032223 |
5 | 3033124322401420243 |
6 | 41310052031333031 |
7 | 2346124015542541 |
oct | 256526045251653 |
9 | 46444082473221 |
10 | 12003101201323 |
11 | 3908539787301 |
12 | 141a346381177 |
13 | 690b7004865b |
14 | 2d6d4b809d91 |
15 | 15c36530504d |
hex | aeab09553ab |
12003101201323 has 2 divisors, whose sum is σ = 12003101201324. Its totient is φ = 12003101201322.
The previous prime is 12003101201303. The next prime is 12003101201347. The reversal of 12003101201323 is 32310210130021.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12003101201323 - 217 = 12003101070251 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 12003101201323.
It is not a weakly prime, because it can be changed into another prime (12003101201303) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6001550600661 + 6001550600662.
It is an arithmetic number, because the mean of its divisors is an integer number (6001550600662).
Almost surely, 212003101201323 is an apocalyptic number.
12003101201323 is a deficient number, since it is larger than the sum of its proper divisors (1).
12003101201323 is an equidigital number, since it uses as much as digits as its factorization.
12003101201323 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 12003101201323 its reverse (32310210130021), we get a palindrome (44313311331344).
The spelling of 12003101201323 in words is "twelve trillion, three billion, one hundred one million, two hundred one thousand, three hundred twenty-three".
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