12003102113333 has 4 divisors (see below), whose sum is σ = 12003109697280. Its totient is φ = 12003094529388.

The previous prime is 12003102113323. The next prime is 12003102113341. The reversal of 12003102113333 is 33331120130021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 12003102113333 - 2¹² = 12003102109237 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12003102113299 and 12003102113308.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12003102113323) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 416135 + ... + 4917252.

It is an arithmetic number, because the mean of its divisors is an integer number (3000777424320).

Almost surely, 2^{12003102113333} is an apocalyptic number.

It is an amenable number.

12003102113333 is a deficient number, since it is larger than the sum of its proper divisors (7583947).

12003102113333 is an equidigital number, since it uses as much as digits as its factorization.

12003102113333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7583946.

The product of its (nonzero) digits is 972, while the sum is 23.

Adding to 12003102113333 its reverse (33331120130021), we get a palindrome (45334222243354).

The spelling of 12003102113333 in words is "twelve trillion, three billion, one hundred two million, one hundred thirteen thousand, three hundred thirty-three".