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12003111030022 = 277643112176511
BaseRepresentation
bin1010111010101011000100…
…1010110100110100000110
31120111111010110000210200121
42232222301022310310012
53033124332410430042
641310053022132154
72346124165226620
oct256526112646406
946444113023617
1012003111030022
11390854428a7a2
12141a34972105a
13690b720aa258
142d6d4cc47c10
1515c3660e7367
hexaeab12b4d06

12003111030022 has 16 divisors (see below), whose sum is σ = 20579454185472. Its totient is φ = 5143517336520.

The previous prime is 12003111029993. The next prime is 12003111030023. The reversal of 12003111030022 is 22003011130021.

It is a junction number, because it is equal to n+sod(n) for n = 12003111029978 and 12003111030005.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12003111030023) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 55981254 + ... + 56195257.

It is an arithmetic number, because the mean of its divisors is an integer number (1286215886592).

Almost surely, 212003111030022 is an apocalyptic number.

12003111030022 is a deficient number, since it is larger than the sum of its proper divisors (8576343155450).

12003111030022 is a wasteful number, since it uses less digits than its factorization.

12003111030022 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 112184163.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 12003111030022 its reverse (22003011130021), we get a palindrome (34006122160043).

Subtracting 12003111030022 from its reverse (22003011130021), we obtain a palindrome (9999900099999).

The spelling of 12003111030022 in words is "twelve trillion, three billion, one hundred eleven million, thirty thousand, twenty-two".

Divisors: 1 2 7 14 7643 15286 53501 107002 112176511 224353022 785235577 1570471154 857365073573 1714730147146 6001555515011 12003111030022