Base | Representation |
---|---|
bin | 11011010010101011110001… |
… | …110101010010001010011011 |
3 | 120201222212112122011112200102 |
4 | 123102223301311102022123 |
5 | 111213042411103043344 |
6 | 1103141324514530015 |
7 | 34165653235133360 |
oct | 3322536165221233 |
9 | 521885478145612 |
10 | 120031213331099 |
11 | 35277a51799914 |
12 | 11566a2a59690b |
13 | 51c8b82ca3065 |
14 | 218d7826b8467 |
15 | dd2449a4ee4e |
hex | 6d2af1d5229b |
120031213331099 has 4 divisors (see below), whose sum is σ = 137178529521264. Its totient is φ = 102883897140936.
The previous prime is 120031213331059. The next prime is 120031213331149. The reversal of 120031213331099 is 990133312130021.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 120031213331099 - 216 = 120031213265563 is a prime.
It is not an unprimeable number, because it can be changed into a prime (120031213331059) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8573658095072 + ... + 8573658095085.
It is an arithmetic number, because the mean of its divisors is an integer number (34294632380316).
Almost surely, 2120031213331099 is an apocalyptic number.
120031213331099 is a deficient number, since it is larger than the sum of its proper divisors (17147316190165).
120031213331099 is an equidigital number, since it uses as much as digits as its factorization.
120031213331099 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 17147316190164.
The product of its (nonzero) digits is 26244, while the sum is 38.
The spelling of 120031213331099 in words is "one hundred twenty trillion, thirty-one billion, two hundred thirteen million, three hundred thirty-one thousand, ninety-nine".
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