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120031213331099 = 717147316190157
BaseRepresentation
bin11011010010101011110001…
…110101010010001010011011
3120201222212112122011112200102
4123102223301311102022123
5111213042411103043344
61103141324514530015
734165653235133360
oct3322536165221233
9521885478145612
10120031213331099
1135277a51799914
1211566a2a59690b
1351c8b82ca3065
14218d7826b8467
15dd2449a4ee4e
hex6d2af1d5229b

120031213331099 has 4 divisors (see below), whose sum is σ = 137178529521264. Its totient is φ = 102883897140936.

The previous prime is 120031213331059. The next prime is 120031213331149. The reversal of 120031213331099 is 990133312130021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 120031213331099 - 216 = 120031213265563 is a prime.

It is not an unprimeable number, because it can be changed into a prime (120031213331059) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8573658095072 + ... + 8573658095085.

It is an arithmetic number, because the mean of its divisors is an integer number (34294632380316).

Almost surely, 2120031213331099 is an apocalyptic number.

120031213331099 is a deficient number, since it is larger than the sum of its proper divisors (17147316190165).

120031213331099 is an equidigital number, since it uses as much as digits as its factorization.

120031213331099 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 17147316190164.

The product of its (nonzero) digits is 26244, while the sum is 38.

The spelling of 120031213331099 in words is "one hundred twenty trillion, thirty-one billion, two hundred thirteen million, three hundred thirty-one thousand, ninety-nine".

Divisors: 1 7 17147316190157 120031213331099