Base | Representation |
---|---|
bin | 11011010010101011110001… |
… | …110101010010001001110011 |
3 | 120201222212112122011112121221 |
4 | 123102223301311102021303 |
5 | 111213042411103043214 |
6 | 1103141324514525511 |
7 | 34165653235133302 |
oct | 3322536165221163 |
9 | 521885478145557 |
10 | 120031213331059 |
11 | 35277a51799888 |
12 | 11566a2a596897 |
13 | 51c8b82ca3034 |
14 | 218d7826b8439 |
15 | dd2449a4ee24 |
hex | 6d2af1d52273 |
120031213331059 has 2 divisors, whose sum is σ = 120031213331060. Its totient is φ = 120031213331058.
The previous prime is 120031213331033. The next prime is 120031213331149. The reversal of 120031213331059 is 950133312130021.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-120031213331059 is a prime.
It is a super-2 number, since 2×1200312133310592 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (120031213331759) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60015606665529 + 60015606665530.
It is an arithmetic number, because the mean of its divisors is an integer number (60015606665530).
Almost surely, 2120031213331059 is an apocalyptic number.
120031213331059 is a deficient number, since it is larger than the sum of its proper divisors (1).
120031213331059 is an equidigital number, since it uses as much as digits as its factorization.
120031213331059 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 14580, while the sum is 34.
The spelling of 120031213331059 in words is "one hundred twenty trillion, thirty-one billion, two hundred thirteen million, three hundred thirty-one thousand, fifty-nine".
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