Base | Representation |
---|---|
bin | 1010111010101011001001… |
… | …0111110001101000110101 |
3 | 1120111111011211222122120122 |
4 | 2232222302113301220311 |
5 | 3033124403041431401 |
6 | 41310055022341325 |
7 | 2346124531543424 |
oct | 256526227615065 |
9 | 46444154878518 |
10 | 12003131202101 |
11 | 3908554708336 |
12 | 141a35442a845 |
13 | 690b76320ab0 |
14 | 2d6d517b92bb |
15 | 15c367c7e21b |
hex | aeab25f1a35 |
12003131202101 has 32 divisors (see below), whose sum is σ = 13631726908800. Its totient is φ = 10477437384960.
The previous prime is 12003131202061. The next prime is 12003131202107. The reversal of 12003131202101 is 10120213130021.
It is not a de Polignac number, because 12003131202101 - 222 = 12003127007797 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 12003131202101.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12003131202107) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 618039371 + ... + 618058791.
It is an arithmetic number, because the mean of its divisors is an integer number (425991465900).
Almost surely, 212003131202101 is an apocalyptic number.
It is an amenable number.
12003131202101 is a deficient number, since it is larger than the sum of its proper divisors (1628595706699).
12003131202101 is a wasteful number, since it uses less digits than its factorization.
12003131202101 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 23909.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 12003131202101 its reverse (10120213130021), we get a palindrome (22123344332122).
The spelling of 12003131202101 in words is "twelve trillion, three billion, one hundred thirty-one million, two hundred two thousand, one hundred one".
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