1200313310414 has 4 divisors (see below), whose sum is σ = 1800469965624. Its totient is φ = 600156655206.

The previous prime is 1200313310411. The next prime is 1200313310429. The reversal of 1200313310414 is 4140133130021.

It is a semiprime because it is the product of two primes.

It is a super-4 number, since 4×1200313310414⁴ (a number of 49 digits) contains 4444 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1200313310414.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1200313310411) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 300078327602 + ... + 300078327605.

It is an arithmetic number, because the mean of its divisors is an integer number (450117491406).

Almost surely, 2^{1200313310414} is an apocalyptic number.

1200313310414 is a deficient number, since it is larger than the sum of its proper divisors (600156655210).

1200313310414 is an equidigital number, since it uses as much as digits as its factorization.

1200313310414 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 600156655209.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 1200313310414 its reverse (4140133130021), we get a palindrome (5340446440435).

The spelling of 1200313310414 in words is "one trillion, two hundred billion, three hundred thirteen million, three hundred ten thousand, four hundred fourteen".