Base | Representation |
---|---|
bin | 10001011101111000001… |
… | …111111010001110000011 |
3 | 11020202012220021000102110 |
4 | 101131320033322032003 |
5 | 124131220201442011 |
6 | 2315225531550403 |
7 | 152501611545333 |
oct | 21357017721603 |
9 | 4222186230373 |
10 | 1200313312131 |
11 | 42306063313a |
12 | 1747665bb403 |
13 | 8925c496abb |
14 | 42149da50c3 |
15 | 21352478ba6 |
hex | 117783fa383 |
1200313312131 has 16 divisors (see below), whose sum is σ = 1687453389440. Its totient is φ = 756831211200.
The previous prime is 1200313312127. The next prime is 1200313312147. The reversal of 1200313312131 is 1312133130021.
It is a happy number.
It is not a de Polignac number, because 1200313312131 - 22 = 1200313312127 is a prime.
It is a super-2 number, since 2×12003133121312 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1200313312098 and 1200313312107.
It is not an unprimeable number, because it can be changed into a prime (1200313312111) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 17484985 + ... + 17553498.
It is an arithmetic number, because the mean of its divisors is an integer number (105465836840).
Almost surely, 21200313312131 is an apocalyptic number.
1200313312131 is a deficient number, since it is larger than the sum of its proper divisors (487140077309).
1200313312131 is a wasteful number, since it uses less digits than its factorization.
1200313312131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 35039106.
The product of its (nonzero) digits is 324, while the sum is 21.
Adding to 1200313312131 its reverse (1312133130021), we get a palindrome (2512446442152).
The spelling of 1200313312131 in words is "one trillion, two hundred billion, three hundred thirteen million, three hundred twelve thousand, one hundred thirty-one".
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