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1200313312127 is a prime number
BaseRepresentation
bin10001011101111000001…
…111111010001101111111
311020202012220021000102022
4101131320033322031333
5124131220201442002
62315225531550355
7152501611545326
oct21357017721577
94222186230368
101200313312127
11423060633136
121747665bb3bb
138925c496ab7
1442149da50bd
1521352478ba2
hex117783fa37f

1200313312127 has 2 divisors, whose sum is σ = 1200313312128. Its totient is φ = 1200313312126.

The previous prime is 1200313312117. The next prime is 1200313312147. The reversal of 1200313312127 is 7212133130021.

It is a weak prime.

It is an emirp because it is prime and its reverse (7212133130021) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1200313312127 - 24 = 1200313312111 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1200313312096 and 1200313312105.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1200313312117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600156656063 + 600156656064.

It is an arithmetic number, because the mean of its divisors is an integer number (600156656064).

Almost surely, 21200313312127 is an apocalyptic number.

1200313312127 is a deficient number, since it is larger than the sum of its proper divisors (1).

1200313312127 is an equidigital number, since it uses as much as digits as its factorization.

1200313312127 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1512, while the sum is 26.

Adding to 1200313312127 its reverse (7212133130021), we get a palindrome (8412446442148).

The spelling of 1200313312127 in words is "one trillion, two hundred billion, three hundred thirteen million, three hundred twelve thousand, one hundred twenty-seven".