Base | Representation |
---|---|
bin | 1010111010101011001011… |
… | …1110101110000100111110 |
3 | 1120111111012120012022201222 |
4 | 2232222302332232010332 |
5 | 3033124413200124014 |
6 | 41310100025233342 |
7 | 2346125014403366 |
oct | 256526276560476 |
9 | 46444176168658 |
10 | 12003141411134 |
11 | 390855a450555 |
12 | 141a357932852 |
13 | 690b78486843 |
14 | 2d6d52cb59a6 |
15 | 15c368ae908e |
hex | aeab2fae13e |
12003141411134 has 4 divisors (see below), whose sum is σ = 18004712116704. Its totient is φ = 6001570705566.
The previous prime is 12003141411097. The next prime is 12003141411179. The reversal of 12003141411134 is 43111414130021.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3000785352782 + ... + 3000785352785.
It is an arithmetic number, because the mean of its divisors is an integer number (4501178029176).
Almost surely, 212003141411134 is an apocalyptic number.
12003141411134 is a deficient number, since it is larger than the sum of its proper divisors (6001570705570).
12003141411134 is an equidigital number, since it uses as much as digits as its factorization.
12003141411134 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6001570705569.
The product of its (nonzero) digits is 1152, while the sum is 26.
Adding to 12003141411134 its reverse (43111414130021), we get a palindrome (55114555541155).
The spelling of 12003141411134 in words is "twelve trillion, three billion, one hundred forty-one million, four hundred eleven thousand, one hundred thirty-four".
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