1200314334013 has 4 divisors (see below), whose sum is σ = 1200733880508. Its totient is φ = 1199894787520.

The previous prime is 1200314334007. The next prime is 1200314334017. The reversal of 1200314334013 is 3104334130021.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 696153272164 + 504161061849 = 834358^2 + 710043^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1200314334013 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1200314334017) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 209768956 + ... + 209774677.

It is an arithmetic number, because the mean of its divisors is an integer number (300183470127).

Almost surely, 2^{1200314334013} is an apocalyptic number.

It is an amenable number.

1200314334013 is a deficient number, since it is larger than the sum of its proper divisors (419546495).

1200314334013 is an equidigital number, since it uses as much as digits as its factorization.

1200314334013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 419546494.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 1200314334013 its reverse (3104334130021), we get a palindrome (4304648464034).

The spelling of 1200314334013 in words is "one trillion, two hundred billion, three hundred fourteen million, three hundred thirty-four thousand, thirteen".