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12003231300000 = 2535547851293
BaseRepresentation
bin1010111010101011100001…
…0101100111100110100000
31120111111102211100011002020
42232222320111213212200
53033130104203100000
641310113000021440
72346130155424143
oct256527025474640
946444384304066
1012003231300000
1139085a6166376
12141a381a61880
13690b90c9a015
142d6d60bd405a
1515c371952ba0
hexaeab85679a0

12003231300000 has 288 divisors, whose sum is σ = 40221067186944. Its totient is φ = 3132754560000.

The previous prime is 12003231299999. The next prime is 12003231300007. The reversal of 12003231300000 is 313230021.

12003231300000 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is not an unprimeable number, because it can be changed into a prime (12003231300007) by changing a digit.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 13674354 + ... + 14525646.

It is an arithmetic number, because the mean of its divisors is an integer number (139656483288).

Almost surely, 212003231300000 is an apocalyptic number.

12003231300000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 12003231300000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (20110533593472).

12003231300000 is an abundant number, since it is smaller than the sum of its proper divisors (28217835886944).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12003231300000 is an frugal number, since it uses more digits than its factorization.

12003231300000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 851378 (or 851350 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 15.

Adding to 12003231300000 its reverse (313230021), we get a palindrome (12003544530021).

The spelling of 12003231300000 in words is "twelve trillion, three billion, two hundred thirty-one million, three hundred thousand".