1200323233303 has 4 divisors (see below), whose sum is σ = 1200495725280. Its totient is φ = 1200150741328.

The previous prime is 1200323233297. The next prime is 1200323233339. The reversal of 1200323233303 is 3033323230021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1200323233303 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1200323233903) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 86235550 + ... + 86249467.

It is an arithmetic number, because the mean of its divisors is an integer number (300123931320).

Almost surely, 2^{1200323233303} is an apocalyptic number.

1200323233303 is a deficient number, since it is larger than the sum of its proper divisors (172491977).

1200323233303 is an equidigital number, since it uses as much as digits as its factorization.

1200323233303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 172491976.

The product of its (nonzero) digits is 5832, while the sum is 25.

Adding to 1200323233303 its reverse (3033323230021), we get a palindrome (4233646463324).

The spelling of 1200323233303 in words is "one trillion, two hundred billion, three hundred twenty-three million, two hundred thirty-three thousand, three hundred three".