Base | Representation |
---|---|
bin | 10001011101111001010… |
… | …011011011010100000011 |
3 | 11020202021010120020011101 |
4 | 101131321103123110003 |
5 | 124131234214330311 |
6 | 2315231403155231 |
7 | 152502215152444 |
oct | 21357123332403 |
9 | 4222233506141 |
10 | 1200331011331 |
11 | 42306a621881 |
12 | 174770515b17 |
13 | 89263052bba |
14 | 4214c4912cb |
15 | 21353cc2ec1 |
hex | 117794db503 |
1200331011331 has 2 divisors, whose sum is σ = 1200331011332. Its totient is φ = 1200331011330.
The previous prime is 1200331011301. The next prime is 1200331011413. The reversal of 1200331011331 is 1331101330021.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1200331011331 - 225 = 1200297456899 is a prime.
It is a super-3 number, since 3×12003310113313 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 1200331011299 and 1200331011308.
It is not a weakly prime, because it can be changed into another prime (1200331011301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600165505665 + 600165505666.
It is an arithmetic number, because the mean of its divisors is an integer number (600165505666).
Almost surely, 21200331011331 is an apocalyptic number.
1200331011331 is a deficient number, since it is larger than the sum of its proper divisors (1).
1200331011331 is an equidigital number, since it uses as much as digits as its factorization.
1200331011331 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 162, while the sum is 19.
Adding to 1200331011331 its reverse (1331101330021), we get a palindrome (2531432341352).
The spelling of 1200331011331 in words is "one trillion, two hundred billion, three hundred thirty-one million, eleven thousand, three hundred thirty-one".
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