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12003312022102 = 26001656011051
BaseRepresentation
bin1010111010101011110100…
…1001100011001001010110
31120111111122110020020222201
42232222331021203021112
53033130240334201402
641310125002115114
72346132155515432
oct256527511431126
946444573206881
1012003312022102
113908637790055
12141a3a4aaba9a
13690ba4920c8b
142d6d6b8079c2
1515c378a9a687
hexaeabd263256

12003312022102 has 4 divisors (see below), whose sum is σ = 18004968033156. Its totient is φ = 6001656011050.

The previous prime is 12003312022043. The next prime is 12003312022123. The reversal of 12003312022102 is 20122021330021.

It is a semiprime because it is the product of two primes.

It is a self number, because there is not a number n which added to its sum of digits gives 12003312022102.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3000828005524 + ... + 3000828005527.

It is an arithmetic number, because the mean of its divisors is an integer number (4501242008289).

Almost surely, 212003312022102 is an apocalyptic number.

12003312022102 is a deficient number, since it is larger than the sum of its proper divisors (6001656011054).

12003312022102 is an equidigital number, since it uses as much as digits as its factorization.

12003312022102 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6001656011053.

The product of its (nonzero) digits is 288, while the sum is 19.

Adding to 12003312022102 its reverse (20122021330021), we get a palindrome (32125333352123).

The spelling of 12003312022102 in words is "twelve trillion, three billion, three hundred twelve million, twenty-two thousand, one hundred two".

Divisors: 1 2 6001656011051 12003312022102