Base | Representation |
---|---|
bin | 10001011101111001010… |
… | …111010010010011100011 |
3 | 11020202021012110121221000 |
4 | 101131321113102103203 |
5 | 124131234444214021 |
6 | 2315231441003043 |
7 | 152502226565112 |
oct | 21357127222343 |
9 | 4222235417830 |
10 | 1200332023011 |
11 | 423070152980 |
12 | 174770923483 |
13 | 89263318524 |
14 | 4214c675c79 |
15 | 21353e22b26 |
hex | 117795d24e3 |
1200332023011 has 64 divisors (see below), whose sum is σ = 1981633167360. Its totient is φ = 711842165280.
The previous prime is 1200332022997. The next prime is 1200332023061. The reversal of 1200332023011 is 1103202330021.
It is a de Polignac number, because none of the positive numbers 2k-1200332023011 is a prime.
It is a super-2 number, since 2×12003320230112 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1200332023061) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 125723940 + ... + 125733486.
It is an arithmetic number, because the mean of its divisors is an integer number (30963018240).
Almost surely, 21200332023011 is an apocalyptic number.
1200332023011 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
1200332023011 is a deficient number, since it is larger than the sum of its proper divisors (781301144349).
1200332023011 is a wasteful number, since it uses less digits than its factorization.
1200332023011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 18621 (or 18615 counting only the distinct ones).
The product of its (nonzero) digits is 216, while the sum is 18.
Adding to 1200332023011 its reverse (1103202330021), we get a palindrome (2303534353032).
The spelling of 1200332023011 in words is "one trillion, two hundred billion, three hundred thirty-two million, twenty-three thousand, eleven".
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