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12003421430000 = 2454711213109013
BaseRepresentation
bin1010111010101100001110…
…1010111010000011110000
31120111111221002002202102002
42232223003222322003300
53033131001341230000
641310143511113132
72346134654463050
oct256530352720360
946444832082362
1012003421430000
113908693517900
12141a4156727a8
13690bc14a9990
142d6d7c167560
1515c3834ac8d5
hexaeac3aba0f0

12003421430000 has 600 divisors, whose sum is σ = 39315578162784. Its totient is φ = 3453500160000.

The previous prime is 12003421429963. The next prime is 12003421430009. The reversal of 12003421430000 is 3412430021.

12003421430000 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12003421430009) by changing a digit.

It is a polite number, since it can be written in 119 ways as a sum of consecutive naturals, for example, 110055494 + ... + 110164506.

Almost surely, 212003421430000 is an apocalyptic number.

12003421430000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 12003421430000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (19657789081392).

12003421430000 is an abundant number, since it is smaller than the sum of its proper divisors (27312156732784).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12003421430000 is a wasteful number, since it uses less digits than its factorization.

12003421430000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 109083 (or 109051 counting only the distinct ones).

The product of its (nonzero) digits is 576, while the sum is 20.

Adding to 12003421430000 its reverse (3412430021), we get a palindrome (12006833860021).

It can be divided in two parts, 12003421 and 430000, that added together give a palindrome (12433421).

The spelling of 12003421430000 in words is "twelve trillion, three billion, four hundred twenty-one million, four hundred thirty thousand".