Base | Representation |
---|---|
bin | 10110010110111010… |
… | …11101000000100001 |
3 | 1010222112120110000112 |
4 | 23023131131000201 |
5 | 144040334233213 |
6 | 5303031101105 |
7 | 603312322001 |
oct | 131335350041 |
9 | 33875513015 |
10 | 12003430433 |
11 | 50aa694a45 |
12 | 23abb11795 |
13 | 1193a96077 |
14 | 81c272001 |
15 | 4a3bebea8 |
hex | 2cb75d021 |
12003430433 has 2 divisors, whose sum is σ = 12003430434. Its totient is φ = 12003430432.
The previous prime is 12003430399. The next prime is 12003430441. The reversal of 12003430433 is 33403430021.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8040350224 + 3963080209 = 89668^2 + 62953^2 .
It is a cyclic number.
It is not a de Polignac number, because 12003430433 - 220 = 12002381857 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12003430399 and 12003430408.
It is not a weakly prime, because it can be changed into another prime (12003430333) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6001715216 + 6001715217.
It is an arithmetic number, because the mean of its divisors is an integer number (6001715217).
Almost surely, 212003430433 is an apocalyptic number.
It is an amenable number.
12003430433 is a deficient number, since it is larger than the sum of its proper divisors (1).
12003430433 is an equidigital number, since it uses as much as digits as its factorization.
12003430433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 23.
Adding to 12003430433 its reverse (33403430021), we get a palindrome (45406860454).
The spelling of 12003430433 in words is "twelve billion, three million, four hundred thirty thousand, four hundred thirty-three".
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