12004140113 has 12 divisors (see below), whose sum is σ = 14573491392. Its totient is φ = 9684010560.

The previous prime is 12004140097. The next prime is 12004140149. The reversal of 12004140113 is 31104140021.

It is a happy number.

It is not a de Polignac number, because 12004140113 - 2⁴ = 12004140097 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (17).

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12004140091 and 12004140100.

It is not an unprimeable number, because it can be changed into a prime (12004146113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 2964893 + ... + 2968938.

It is an arithmetic number, because the mean of its divisors is an integer number (1214457616).

Almost surely, 2^12004140113 is an apocalyptic number.

It is an amenable number.

12004140113 is a deficient number, since it is larger than the sum of its proper divisors (2569351279).

12004140113 is an equidigital number, since it uses as much as digits as its factorization.

12004140113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5933872 (or 5933855 counting only the distinct ones).

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 12004140113 its reverse (31104140021), we get a palindrome (43108280134).

The spelling of 12004140113 in words is "twelve billion, four million, one hundred forty thousand, one hundred thirteen".