1200414113 has 4 divisors (see below), whose sum is σ = 1229692548. Its totient is φ = 1171135680.

The previous prime is 1200414079. The next prime is 1200414133. The reversal of 1200414113 is 3114140021.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 337934689 + 862479424 = 18383^2 + 29368^2 .

It is a cyclic number.

It is not a de Polignac number, because 1200414113 - 2⁶ = 1200414049 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1200414091 and 1200414100.

It is not an unprimeable number, because it can be changed into a prime (1200414133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14639156 + ... + 14639237.

It is an arithmetic number, because the mean of its divisors is an integer number (307423137).

Almost surely, 2^1200414113 is an apocalyptic number.

It is an amenable number.

1200414113 is a deficient number, since it is larger than the sum of its proper divisors (29278435).

1200414113 is an equidigital number, since it uses as much as digits as its factorization.

1200414113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 29278434.

The product of its (nonzero) digits is 96, while the sum is 17.

The square root of 1200414113 is about 34646.9928420924. The cubic root of 1200414113 is about 1062.7807942151.

Adding to 1200414113 its reverse (3114140021), we get a palindrome (4314554134).

The spelling of 1200414113 in words is "one billion, two hundred million, four hundred fourteen thousand, one hundred thirteen".