1200420121013 has 4 divisors (see below), whose sum is σ = 1200539706720. Its totient is φ = 1200300535308.

The previous prime is 1200420121007. The next prime is 1200420121037. The reversal of 1200420121013 is 3101210240021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1200420121013 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1200420120982 and 1200420121000.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1200420121003) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 59777795 + ... + 59797872.

It is an arithmetic number, because the mean of its divisors is an integer number (300134926680).

Almost surely, 2^{1200420121013} is an apocalyptic number.

It is an amenable number.

1200420121013 is a deficient number, since it is larger than the sum of its proper divisors (119585707).

1200420121013 is a wasteful number, since it uses less digits than its factorization.

1200420121013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 119585706.

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 1200420121013 its reverse (3101210240021), we get a palindrome (4301630361034).

The spelling of 1200420121013 in words is "one trillion, two hundred billion, four hundred twenty million, one hundred twenty-one thousand, thirteen".