Base | Representation |
---|---|
bin | 110111111001100010… |
… | …0010111010001110011 |
3 | 102110211221102202022112 |
4 | 1233303010113101303 |
5 | 3431321240440103 |
6 | 131051355155535 |
7 | 11446520136035 |
oct | 1576304272163 |
9 | 373757382275 |
10 | 120042124403 |
11 | 46a00716883 |
12 | 1b321a45bab |
13 | b420b45b56 |
14 | 5b4ab8dc55 |
15 | 31c8a26cd8 |
hex | 1bf3117473 |
120042124403 has 2 divisors, whose sum is σ = 120042124404. Its totient is φ = 120042124402.
The previous prime is 120042124289. The next prime is 120042124451. The reversal of 120042124403 is 304421240021.
It is a strong prime.
It is an emirp because it is prime and its reverse (304421240021) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 120042124403 - 212 = 120042120307 is a prime.
It is a super-2 number, since 2×1200421244032 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (120042123403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60021062201 + 60021062202.
It is an arithmetic number, because the mean of its divisors is an integer number (60021062202).
Almost surely, 2120042124403 is an apocalyptic number.
120042124403 is a deficient number, since it is larger than the sum of its proper divisors (1).
120042124403 is an equidigital number, since it uses as much as digits as its factorization.
120042124403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1536, while the sum is 23.
Adding to 120042124403 its reverse (304421240021), we get a palindrome (424463364424).
The spelling of 120042124403 in words is "one hundred twenty billion, forty-two million, one hundred twenty-four thousand, four hundred three".
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