Base | Representation |
---|---|
bin | 11011010011010000000011… |
… | …111001100000010011100001 |
3 | 120202010121002200010221100222 |
4 | 123103100003321200103201 |
5 | 111214212202302230103 |
6 | 1103211250343452425 |
7 | 34201532526032243 |
oct | 3323200371402341 |
9 | 522117080127328 |
10 | 120070171133153 |
11 | 3529252342213a |
12 | 115724a1457115 |
13 | 51cc751162337 |
14 | 21915da6b2093 |
15 | dd3479cbc638 |
hex | 6d3403e604e1 |
120070171133153 has 2 divisors, whose sum is σ = 120070171133154. Its totient is φ = 120070171133152.
The previous prime is 120070171133147. The next prime is 120070171133197. The reversal of 120070171133153 is 351331171070021.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 63389494909504 + 56680676223649 = 7961752^2 + 7528657^2 .
It is a cyclic number.
It is not a de Polignac number, because 120070171133153 - 214 = 120070171116769 is a prime.
It is not a weakly prime, because it can be changed into another prime (120070171133113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60035085566576 + 60035085566577.
It is an arithmetic number, because the mean of its divisors is an integer number (60035085566577).
Almost surely, 2120070171133153 is an apocalyptic number.
It is an amenable number.
120070171133153 is a deficient number, since it is larger than the sum of its proper divisors (1).
120070171133153 is an equidigital number, since it uses as much as digits as its factorization.
120070171133153 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13230, while the sum is 35.
The spelling of 120070171133153 in words is "one hundred twenty trillion, seventy billion, one hundred seventy-one million, one hundred thirty-three thousand, one hundred fifty-three".
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