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120070171133153 is a prime number
BaseRepresentation
bin11011010011010000000011…
…111001100000010011100001
3120202010121002200010221100222
4123103100003321200103201
5111214212202302230103
61103211250343452425
734201532526032243
oct3323200371402341
9522117080127328
10120070171133153
113529252342213a
12115724a1457115
1351cc751162337
1421915da6b2093
15dd3479cbc638
hex6d3403e604e1

120070171133153 has 2 divisors, whose sum is σ = 120070171133154. Its totient is φ = 120070171133152.

The previous prime is 120070171133147. The next prime is 120070171133197. The reversal of 120070171133153 is 351331171070021.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 63389494909504 + 56680676223649 = 7961752^2 + 7528657^2 .

It is a cyclic number.

It is not a de Polignac number, because 120070171133153 - 214 = 120070171116769 is a prime.

It is not a weakly prime, because it can be changed into another prime (120070171133113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60035085566576 + 60035085566577.

It is an arithmetic number, because the mean of its divisors is an integer number (60035085566577).

Almost surely, 2120070171133153 is an apocalyptic number.

It is an amenable number.

120070171133153 is a deficient number, since it is larger than the sum of its proper divisors (1).

120070171133153 is an equidigital number, since it uses as much as digits as its factorization.

120070171133153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 13230, while the sum is 35.

The spelling of 120070171133153 in words is "one hundred twenty trillion, seventy billion, one hundred seventy-one million, one hundred thirty-three thousand, one hundred fifty-three".