Base | Representation |
---|---|
bin | 11011010011010011000111… |
… | …100010011000101101100011 |
3 | 120202010220120102022201201210 |
4 | 123103103013202120231203 |
5 | 111214240413033011300 |
6 | 1103212552154201203 |
7 | 34202010052636050 |
oct | 3323230742305543 |
9 | 522126512281653 |
10 | 120073453407075 |
11 | 3529395815a113 |
12 | 11573058723203 |
13 | 51ccb5517925c |
14 | 219182c596027 |
15 | dd35bd01d050 |
hex | 6d34c7898b63 |
120073453407075 has 48 divisors (see below), whose sum is σ = 227373800645376. Its totient is φ = 54771652636800.
The previous prime is 120073453407007. The next prime is 120073453407107. The reversal of 120073453407075 is 570704354370021.
120073453407075 is digitally balanced in base 4, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 120073453407075 - 27 = 120073453406947 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 247817997 + ... + 248302046.
It is an arithmetic number, because the mean of its divisors is an integer number (4736954180112).
Almost surely, 2120073453407075 is an apocalyptic number.
120073453407075 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
120073453407075 is a deficient number, since it is larger than the sum of its proper divisors (107300347238301).
120073453407075 is a wasteful number, since it uses less digits than its factorization.
120073453407075 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 496120524 (or 496120519 counting only the distinct ones).
The product of its (nonzero) digits is 2469600, while the sum is 48.
The spelling of 120073453407075 in words is "one hundred twenty trillion, seventy-three billion, four hundred fifty-three million, four hundred seven thousand, seventy-five".
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