Base | Representation |
---|---|
bin | 1010111011000101001011… |
… | …1100101011111100010001 |
3 | 1120112011012221000112020221 |
4 | 2232301102330223330101 |
5 | 3033233211232344303 |
6 | 41313212325033041 |
7 | 2346462655210441 |
oct | 256612274537421 |
9 | 46464187015227 |
10 | 12010120199953 |
11 | 3910510827917 |
12 | 141b784b55781 |
13 | 69171b273c95 |
14 | 2d7415ab0121 |
15 | 15c6266234bd |
hex | aec52f2bf11 |
12010120199953 has 2 divisors, whose sum is σ = 12010120199954. Its totient is φ = 12010120199952.
The previous prime is 12010120199879. The next prime is 12010120200047. The reversal of 12010120199953 is 35999102101021.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12009946698369 + 173501584 = 3465537^2 + 13172^2 .
It is a cyclic number.
It is not a de Polignac number, because 12010120199953 - 213 = 12010120191761 is a prime.
It is not a weakly prime, because it can be changed into another prime (12010120119953) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6005060099976 + 6005060099977.
It is an arithmetic number, because the mean of its divisors is an integer number (6005060099977).
Almost surely, 212010120199953 is an apocalyptic number.
It is an amenable number.
12010120199953 is a deficient number, since it is larger than the sum of its proper divisors (1).
12010120199953 is an equidigital number, since it uses as much as digits as its factorization.
12010120199953 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 43740, while the sum is 43.
The spelling of 12010120199953 in words is "twelve trillion, ten billion, one hundred twenty million, one hundred ninety-nine thousand, nine hundred fifty-three".
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