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120101255135153 is a prime number
BaseRepresentation
bin11011010011101101000000…
…101001100011111110110001
3120202020120022222011211221022
4123103231000221203332301
5111220214332303311103
61103233431021505225
734204013030503625
oct3323550051437661
9522216288154838
10120101255135153
11352a4724543996
1211578517412215
135202665c96426
142192d08a93185
15dd4198b6c138
hex6d3b40a63fb1

120101255135153 has 2 divisors, whose sum is σ = 120101255135154. Its totient is φ = 120101255135152.

The previous prime is 120101255135149. The next prime is 120101255135179. The reversal of 120101255135153 is 351531552101021.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 117992103081889 + 2109152053264 = 10862417^2 + 1452292^2 .

It is an emirp because it is prime and its reverse (351531552101021) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 120101255135153 - 22 = 120101255135149 is a prime.

It is a super-2 number, since 2×1201012551351532 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (120101255135123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60050627567576 + 60050627567577.

It is an arithmetic number, because the mean of its divisors is an integer number (60050627567577).

Almost surely, 2120101255135153 is an apocalyptic number.

It is an amenable number.

120101255135153 is a deficient number, since it is larger than the sum of its proper divisors (1).

120101255135153 is an equidigital number, since it uses as much as digits as its factorization.

120101255135153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 22500, while the sum is 35.

The spelling of 120101255135153 in words is "one hundred twenty trillion, one hundred one billion, two hundred fifty-five million, one hundred thirty-five thousand, one hundred fifty-three".