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120101334420134 = 21741209916432613
BaseRepresentation
bin11011010011101101000101…
…011000000000101010100110
3120202020120112111100221111002
4123103231011120000222212
5111220220013102421014
61103233442533113302
734204015012431314
oct3323550530005246
9522216474327432
10120101334420134
11352a4765276971
1211578539a88832
135202679536212
142192d154110b4
15dd41a0acddde
hex6d3b45600aa6

120101334420134 has 16 divisors (see below), whose sum is σ = 180341365604400. Its totient is φ = 59987578758240.

The previous prime is 120101334420131. The next prime is 120101334420149. The reversal of 120101334420134 is 431024433101021.

It is a junction number, because it is equal to n+sod(n) for n = 120101334420097 and 120101334420106.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (120101334420131) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 907589 + ... + 15525024.

It is an arithmetic number, because the mean of its divisors is an integer number (11271335350275).

Almost surely, 2120101334420134 is an apocalyptic number.

120101334420134 is a deficient number, since it is larger than the sum of its proper divisors (60240031184266).

120101334420134 is a wasteful number, since it uses less digits than its factorization.

120101334420134 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 16436455.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 120101334420134 its reverse (431024433101021), we get a palindrome (551125767521155).

The spelling of 120101334420134 in words is "one hundred twenty trillion, one hundred one billion, three hundred thirty-four million, four hundred twenty thousand, one hundred thirty-four".

Divisors: 1 2 1741 2099 3482 4198 3654359 7308718 16432613 32865226 28609179233 34492054687 57218358466 68984109374 60050667210067 120101334420134