Base | Representation |
---|---|
bin | 1010111011000110001111… |
… | …1000110111111110101001 |
3 | 1120112011221201211001202011 |
4 | 2232301203320313332221 |
5 | 3033234302012211403 |
6 | 41313300440435521 |
7 | 2346503006040103 |
oct | 256614370677651 |
9 | 46464851731664 |
10 | 12010404413353 |
11 | 39106471a9625 |
12 | 141b844178ba1 |
13 | 6917651053a8 |
14 | 2d7441734573 |
15 | 15c641564a6d |
hex | aec63e37fa9 |
12010404413353 has 2 divisors, whose sum is σ = 12010404413354. Its totient is φ = 12010404413352.
The previous prime is 12010404413297. The next prime is 12010404413401. The reversal of 12010404413353 is 35331440401021.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8802537146649 + 3207867266704 = 2966907^2 + 1791052^2 .
It is an emirp because it is prime and its reverse (35331440401021) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12010404413353 - 213 = 12010404405161 is a prime.
It is not a weakly prime, because it can be changed into another prime (12010404413753) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6005202206676 + 6005202206677.
It is an arithmetic number, because the mean of its divisors is an integer number (6005202206677).
Almost surely, 212010404413353 is an apocalyptic number.
It is an amenable number.
12010404413353 is a deficient number, since it is larger than the sum of its proper divisors (1).
12010404413353 is an equidigital number, since it uses as much as digits as its factorization.
12010404413353 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 12010404413353 its reverse (35331440401021), we get a palindrome (47341844814374).
The spelling of 12010404413353 in words is "twelve trillion, ten billion, four hundred four million, four hundred thirteen thousand, three hundred fifty-three".
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