12011000009993 has 2 divisors, whose sum is σ = 12011000009994. Its totient is φ = 12011000009992.

The previous prime is 12011000009929. The next prime is 12011000010067. The reversal of 12011000009993 is 39990000011021.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11801993772409 + 209006237584 = 3435403^2 + 457172^2 .

It is a cyclic number.

It is not a de Polignac number, because 12011000009993 - 2⁶ = 12011000009929 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (12011000099993) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6005500004996 + 6005500004997.

It is an arithmetic number, because the mean of its divisors is an integer number (6005500004997).

Almost surely, 2^{12011000009993} is an apocalyptic number.

It is an amenable number.

12011000009993 is a deficient number, since it is larger than the sum of its proper divisors (1).

12011000009993 is an equidigital number, since it uses as much as digits as its factorization.

12011000009993 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4374, while the sum is 35.

The spelling of 12011000009993 in words is "twelve trillion, eleven billion, nine thousand, nine hundred ninety-three".