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12011000314 = 26005500157
BaseRepresentation
bin10110010111110100…
…10101000111111010
31011000001211000221111
423023322111013322
5144044304002224
65303501230534
7603433550425
oct131372250772
934001730844
1012011000314
115103995345
1223b256244a
1311955167a1
1481d2829bc
154a46e4d94
hex2cbe951fa

12011000314 has 4 divisors (see below), whose sum is σ = 18016500474. Its totient is φ = 6005500156.

The previous prime is 12011000311. The next prime is 12011000317. The reversal of 12011000314 is 41300011021.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (12011000311) and next prime (12011000317).

It can be written as a sum of positive squares in only one way, i.e., 11139747025 + 871253289 = 105545^2 + 29517^2 .

It is a junction number, because it is equal to n+sod(n) for n = 12011000294 and 12011000303.

It is not an unprimeable number, because it can be changed into a prime (12011000311) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3002750077 + ... + 3002750080.

Almost surely, 212011000314 is an apocalyptic number.

12011000314 is a deficient number, since it is larger than the sum of its proper divisors (6005500160).

12011000314 is an equidigital number, since it uses as much as digits as its factorization.

12011000314 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6005500159.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 12011000314 its reverse (41300011021), we get a palindrome (53311011335).

The spelling of 12011000314 in words is "twelve billion, eleven million, three hundred fourteen", and thus it is an aban number.

Divisors: 1 2 6005500157 12011000314