Base | Representation |
---|---|
bin | 1010111011001000011110… |
… | …0001101111111101010011 |
3 | 1120112020111101220102111211 |
4 | 2232302013201233331103 |
5 | 3033242013044042323 |
6 | 41313440040120551 |
7 | 2346523556204116 |
oct | 256620741577523 |
9 | 46466441812454 |
10 | 12011002330963 |
11 | 3910923764a09 |
12 | 141b990466157 |
13 | 69182bc521ac |
14 | 2d749acd857d |
15 | 15c678cc070d |
hex | aec8786ff53 |
12011002330963 has 2 divisors, whose sum is σ = 12011002330964. Its totient is φ = 12011002330962.
The previous prime is 12011002330939. The next prime is 12011002331033. The reversal of 12011002330963 is 36903320011021.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12011002330963 - 29 = 12011002330451 is a prime.
It is not a weakly prime, because it can be changed into another prime (12011002330913) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6005501165481 + 6005501165482.
It is an arithmetic number, because the mean of its divisors is an integer number (6005501165482).
Almost surely, 212011002330963 is an apocalyptic number.
12011002330963 is a deficient number, since it is larger than the sum of its proper divisors (1).
12011002330963 is an equidigital number, since it uses as much as digits as its factorization.
12011002330963 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5832, while the sum is 31.
Adding to 12011002330963 its reverse (36903320011021), we get a palindrome (48914322341984).
The spelling of 12011002330963 in words is "twelve trillion, eleven billion, two million, three hundred thirty thousand, nine hundred sixty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.087 sec. • engine limits •