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1201101314222 = 2600550657111
BaseRepresentation
bin10001011110100111001…
…101111001100010101110
311020211020211000200002002
4101132213031321202232
5124134323414023342
62315440041332302
7152530260501455
oct21364715714256
94224224020062
101201101314222
11423425419837
12174946497092
1389356808924
14421c28c9b9c
152139b730d32
hex117a73798ae

1201101314222 has 4 divisors (see below), whose sum is σ = 1801651971336. Its totient is φ = 600550657110.

The previous prime is 1201101314209. The next prime is 1201101314227. The reversal of 1201101314222 is 2224131011021.

It is a semiprime because it is the product of two primes.

It is a junction number, because it is equal to n+sod(n) for n = 1201101314194 and 1201101314203.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1201101314227) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 300275328554 + ... + 300275328557.

It is an arithmetic number, because the mean of its divisors is an integer number (450412992834).

Almost surely, 21201101314222 is an apocalyptic number.

1201101314222 is a deficient number, since it is larger than the sum of its proper divisors (600550657114).

1201101314222 is an equidigital number, since it uses as much as digits as its factorization.

1201101314222 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 600550657113.

The product of its (nonzero) digits is 192, while the sum is 20.

Adding to 1201101314222 its reverse (2224131011021), we get a palindrome (3425232325243).

The spelling of 1201101314222 in words is "one trillion, two hundred one billion, one hundred one million, three hundred fourteen thousand, two hundred twenty-two".

Divisors: 1 2 600550657111 1201101314222