Base | Representation |
---|---|
bin | 11011010011110110001100… |
… | …001010111100100001001011 |
3 | 120202021111202220211011110101 |
4 | 123103312030022330201023 |
5 | 111220400024200042303 |
6 | 1103242141055030231 |
7 | 34204512220435222 |
oct | 3323661412744113 |
9 | 522244686734411 |
10 | 120111112112203 |
11 | 352a8922551713 |
12 | 1157a40850b377 |
13 | 5203577158624 |
14 | 21935a1c25cb9 |
15 | dd45741c7d1d |
hex | 6d3d8c2bc84b |
120111112112203 has 2 divisors, whose sum is σ = 120111112112204. Its totient is φ = 120111112112202.
The previous prime is 120111112112023. The next prime is 120111112112239. The reversal of 120111112112203 is 302211211111021.
Together with previous prime (120111112112023) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 120111112112203 - 241 = 117912088856651 is a prime.
It is not a weakly prime, because it can be changed into another prime (120111112113203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60055556056101 + 60055556056102.
It is an arithmetic number, because the mean of its divisors is an integer number (60055556056102).
Almost surely, 2120111112112203 is an apocalyptic number.
120111112112203 is a deficient number, since it is larger than the sum of its proper divisors (1).
120111112112203 is an equidigital number, since it uses as much as digits as its factorization.
120111112112203 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 19.
Adding to 120111112112203 its reverse (302211211111021), we get a palindrome (422322323223224).
The spelling of 120111112112203 in words is "one hundred twenty trillion, one hundred eleven billion, one hundred twelve million, one hundred twelve thousand, two hundred three".
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