Base | Representation |
---|---|
bin | 1010111011001000111000… |
… | …0101010100111110111001 |
3 | 1120112020210001212111102011 |
4 | 2232302032011110332321 |
5 | 3033242224223232303 |
6 | 41313455005405521 |
7 | 2346526363124464 |
oct | 256621605247671 |
9 | 46466701774364 |
10 | 12011112320953 |
11 | 391097a85a029 |
12 | 141ba012698a1 |
13 | 691848982b25 |
14 | 2d74ab76a2db |
15 | 15c68379a16d |
hex | aec8e154fb9 |
12011112320953 has 2 divisors, whose sum is σ = 12011112320954. Its totient is φ = 12011112320952.
The previous prime is 12011112320903. The next prime is 12011112321073. The reversal of 12011112320953 is 35902321111021.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12008359534864 + 2752786089 = 3465308^2 + 52467^2 .
It is a cyclic number.
It is not a de Polignac number, because 12011112320953 - 225 = 12011078766521 is a prime.
It is not a weakly prime, because it can be changed into another prime (12011112320903) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6005556160476 + 6005556160477.
It is an arithmetic number, because the mean of its divisors is an integer number (6005556160477).
Almost surely, 212011112320953 is an apocalyptic number.
It is an amenable number.
12011112320953 is a deficient number, since it is larger than the sum of its proper divisors (1).
12011112320953 is an equidigital number, since it uses as much as digits as its factorization.
12011112320953 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3240, while the sum is 31.
Adding to 12011112320953 its reverse (35902321111021), we get a palindrome (47913433431974).
The spelling of 12011112320953 in words is "twelve trillion, eleven billion, one hundred twelve million, three hundred twenty thousand, nine hundred fifty-three".
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