Base | Representation |
---|---|
bin | 110111111011100101… |
… | …1111010010111110001 |
3 | 102111000202102202201001 |
4 | 1233313023322113301 |
5 | 3431441432241032 |
6 | 131102304042001 |
7 | 11451316312456 |
oct | 1576713722761 |
9 | 374022382631 |
10 | 120111212017 |
11 | 46a36714385 |
12 | 1b341003301 |
13 | b4322552b4 |
14 | 5b5601582d |
15 | 31ceb223e7 |
hex | 1bf72fa5f1 |
120111212017 has 2 divisors, whose sum is σ = 120111212018. Its totient is φ = 120111212016.
The previous prime is 120111211993. The next prime is 120111212027. The reversal of 120111212017 is 710212111021.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 115339027456 + 4772184561 = 339616^2 + 69081^2 .
It is a cyclic number.
It is not a de Polignac number, because 120111212017 - 215 = 120111179249 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 120111211985 and 120111212003.
It is not a weakly prime, because it can be changed into another prime (120111212027) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60055606008 + 60055606009.
It is an arithmetic number, because the mean of its divisors is an integer number (60055606009).
Almost surely, 2120111212017 is an apocalyptic number.
It is an amenable number.
120111212017 is a deficient number, since it is larger than the sum of its proper divisors (1).
120111212017 is an equidigital number, since it uses as much as digits as its factorization.
120111212017 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 56, while the sum is 19.
Adding to 120111212017 its reverse (710212111021), we get a palindrome (830323323038).
The spelling of 120111212017 in words is "one hundred twenty billion, one hundred eleven million, two hundred twelve thousand, seventeen".
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