Base | Representation |
---|---|
bin | 1010111011001000111011… |
… | …0111001110111111010011 |
3 | 1120112020210222111011102202 |
4 | 2232302032313032333103 |
5 | 3033242241100403403 |
6 | 41313500154033415 |
7 | 2346526612253354 |
oct | 256621667167723 |
9 | 46466728434382 |
10 | 12011125403603 |
11 | 3910987185237 |
12 | 141ba0571886b |
13 | 69184b5b3841 |
14 | 2d74ad3b3d2b |
15 | 15c6849d1688 |
hex | aec8edcefd3 |
12011125403603 has 2 divisors, whose sum is σ = 12011125403604. Its totient is φ = 12011125403602.
The previous prime is 12011125403539. The next prime is 12011125403713. The reversal of 12011125403603 is 30630452111021.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12011125403603 - 26 = 12011125403539 is a prime.
It is a super-2 number, since 2×120111254036032 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (12011125405603) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6005562701801 + 6005562701802.
It is an arithmetic number, because the mean of its divisors is an integer number (6005562701802).
Almost surely, 212011125403603 is an apocalyptic number.
12011125403603 is a deficient number, since it is larger than the sum of its proper divisors (1).
12011125403603 is an equidigital number, since it uses as much as digits as its factorization.
12011125403603 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4320, while the sum is 29.
Adding to 12011125403603 its reverse (30630452111021), we get a palindrome (42641577514624).
The spelling of 12011125403603 in words is "twelve trillion, eleven billion, one hundred twenty-five million, four hundred three thousand, six hundred three".
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