12011133101953 has 2 divisors, whose sum is σ = 12011133101954. Its totient is φ = 12011133101952.

The previous prime is 12011133101873. The next prime is 12011133101959. The reversal of 12011133101953 is 35910133111021.

12011133101953 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12010605159424 + 527942529 = 3465632^2 + 22977^2 .

It is a cyclic number.

It is not a de Polignac number, because 12011133101953 - 2⁹ = 12011133101441 is a prime.

It is not a weakly prime, because it can be changed into another prime (12011133101959) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6005566550976 + 6005566550977.

It is an arithmetic number, because the mean of its divisors is an integer number (6005566550977).

Almost surely, 2^{12011133101953} is an apocalyptic number.

It is an amenable number.

12011133101953 is a deficient number, since it is larger than the sum of its proper divisors (1).

12011133101953 is an equidigital number, since it uses as much as digits as its factorization.

12011133101953 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2430, while the sum is 31.

Adding to 12011133101953 its reverse (35910133111021), we get a palindrome (47921266212974).

The spelling of 12011133101953 in words is "twelve trillion, eleven billion, one hundred thirty-three million, one hundred one thousand, nine hundred fifty-three".