1201114744807 has 8 divisors (see below), whose sum is σ = 1262485574496. Its totient is φ = 1140506285952.

The previous prime is 1201114744777. The next prime is 1201114744813. The reversal of 1201114744807 is 7084474111021.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a de Polignac number, because none of the positive numbers 2^k-1201114744807 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1201114744807.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1201114744847) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 190589478 + ... + 190595779.

It is an arithmetic number, because the mean of its divisors is an integer number (157810696812).

Almost surely, 2^{1201114744807} is an apocalyptic number.

1201114744807 is a deficient number, since it is larger than the sum of its proper divisors (61370829689).

1201114744807 is a wasteful number, since it uses less digits than its factorization.

1201114744807 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 381185417.

The product of its (nonzero) digits is 50176, while the sum is 40.

Adding to 1201114744807 its reverse (7084474111021), we get a palindrome (8285588855828).

The spelling of 1201114744807 in words is "one trillion, two hundred one billion, one hundred fourteen million, seven hundred forty-four thousand, eight hundred seven".