Base | Representation |
---|---|
bin | 10001011110101000000… |
… | …001001000100000001111 |
3 | 11020211021202022000102122 |
4 | 101132220001020200033 |
5 | 124134340333313342 |
6 | 2315441241243155 |
7 | 152530512610013 |
oct | 21365001104017 |
9 | 4224252260378 |
10 | 1201114744847 |
11 | 423431a62426 |
12 | 17494aa934bb |
13 | 8935952bb44 |
14 | 421c45c4543 |
15 | 2139c9d54d2 |
hex | 117a804880f |
1201114744847 has 2 divisors, whose sum is σ = 1201114744848. Its totient is φ = 1201114744846.
The previous prime is 1201114744831. The next prime is 1201114744889. The reversal of 1201114744847 is 7484474111021.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1201114744847 - 24 = 1201114744831 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1201114744798 and 1201114744807.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1201114743847) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600557372423 + 600557372424.
It is an arithmetic number, because the mean of its divisors is an integer number (600557372424).
Almost surely, 21201114744847 is an apocalyptic number.
1201114744847 is a deficient number, since it is larger than the sum of its proper divisors (1).
1201114744847 is an equidigital number, since it uses as much as digits as its factorization.
1201114744847 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 200704, while the sum is 44.
Adding to 1201114744847 its reverse (7484474111021), we get a palindrome (8685588855868).
The spelling of 1201114744847 in words is "one trillion, two hundred one billion, one hundred fourteen million, seven hundred forty-four thousand, eight hundred forty-seven".
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