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12011201133202 = 26005600566601
BaseRepresentation
bin1010111011001001001101…
…1000000111101010010010
31120112021000020222121220201
42232302103120013222102
53033242414442230302
641313511501125414
72346531522042355
oct256622330075222
946467006877821
1012011201133202
113910a159a9a87
12141ba26b5986a
136918611aa25b
142d74b948829c
1515c68b48ec87
hexaec93607a92

12011201133202 has 4 divisors (see below), whose sum is σ = 18016801699806. Its totient is φ = 6005600566600.

The previous prime is 12011201133103. The next prime is 12011201133203. The reversal of 12011201133202 is 20233110211021.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 8884638065521 + 3126563067681 = 2980711^2 + 1768209^2 .

It is a self number, because there is not a number n which added to its sum of digits gives 12011201133202.

It is not an unprimeable number, because it can be changed into a prime (12011201133203) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3002800283299 + ... + 3002800283302.

Almost surely, 212011201133202 is an apocalyptic number.

12011201133202 is a deficient number, since it is larger than the sum of its proper divisors (6005600566604).

12011201133202 is an equidigital number, since it uses as much as digits as its factorization.

12011201133202 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6005600566603.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 12011201133202 its reverse (20233110211021), we get a palindrome (32244311344223).

The spelling of 12011201133202 in words is "twelve trillion, eleven billion, two hundred one million, one hundred thirty-three thousand, two hundred two".

Divisors: 1 2 6005600566601 12011201133202