Base | Representation |
---|---|
bin | 1010111011001001001101… |
… | …1000000111101010010011 |
3 | 1120112021000020222121220202 |
4 | 2232302103120013222103 |
5 | 3033242414442230303 |
6 | 41313511501125415 |
7 | 2346531522042356 |
oct | 256622330075223 |
9 | 46467006877822 |
10 | 12011201133203 |
11 | 3910a159a9a88 |
12 | 141ba26b5986b |
13 | 6918611aa25c |
14 | 2d74b948829d |
15 | 15c68b48ec88 |
hex | aec93607a93 |
12011201133203 has 2 divisors, whose sum is σ = 12011201133204. Its totient is φ = 12011201133202.
The previous prime is 12011201133103. The next prime is 12011201133289. The reversal of 12011201133203 is 30233110211021.
It is a happy number.
12011201133203 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12011201133203 - 232 = 12006906165907 is a prime.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (12011201133103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6005600566601 + 6005600566602.
It is an arithmetic number, because the mean of its divisors is an integer number (6005600566602).
Almost surely, 212011201133203 is an apocalyptic number.
12011201133203 is a deficient number, since it is larger than the sum of its proper divisors (1).
12011201133203 is an equidigital number, since it uses as much as digits as its factorization.
12011201133203 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 20.
Adding to 12011201133203 its reverse (30233110211021), we get a palindrome (42244311344224).
The spelling of 12011201133203 in words is "twelve trillion, eleven billion, two hundred one million, one hundred thirty-three thousand, two hundred three".
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